a man gets rupees 100 per day if if he works, but he is fined by rupees 10 if he is absent. in the whole month of June he received rupees 1900 only how many days did he work?
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Answer :
- The man worked for 20 days in June
Given :
- A man gets rupees 100 per day if he works
- He is fined by rupees 10 if he get absent
- Whole month of June he received rupees 1900
To find :
- How many days did he work
Solution :
- Let the man works days be x
- Let the man works absent days be y
Then , June has 30 days so ,
- x + y = 30
- So, x + y = 30 is first equation (1)
According To Question ,
Given,
- a man gets rupees 100 per day if if he works, but he is fined by rupees 10 if he is absent. in the whole month of June he received rupees 1900 only and also Given that working days be x and absent days be y
》100x + 10y = 1900
》10x - y = 190
- 10x - y = 190 is second equation (2)
Now , Adding eq (1) and (2) we get ,
》x + y = 30 + 10x - y = 190
》11x = 220
》x = 220/11
》x = 20
Hence , The man worked for 20 days in June
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