Question

A man gives 20% of his property to his wife and then also gives 30% of the remaining property to his son .If the sum now left with him is rs.6720 ,find the value of the original property

Answer 1

let he had rs 100.
gave 20% to his wife so she got = 100× 20/100 = 20
gave 30% of the remaining to his son so he got
= (100 - 20) × 30/100 = 24
sum remaining with him = 100 - 20 - 24 = 56
if remaining is 56 then sum = 100
if remaining is 1 then sum = (100/56)
if remaining is 6720 then sum
= (100/56) × 6720
= 100 × 120
= 12000

Answer 2

Step-by-step explanation:

Rule a+b+ab/100

20+30 + 600 / 100 = 56

then value of original property = 100*6720/56=RS 12000 ans