Math, asked by sharukhkhan098760987, 6 months ago

A man gives 30% of his property to his wife,50% of the rest to his son and divides equally rest of his property among his tow daughters. if each of his daughter receives Rs 49000 find his property​

Answers

Answered by reeyu22
3

Answer:

GIVEN -

  • 30% PROPERTY TO HIS WIFE
  • 50% OF REST TO HIS SON
  • REST TO HIS 2 DAUGHTER

TO FIND -

  • TOTAL PROPERTY

SOLUTION -

Let the total property be X

30% to his wife.

his wife gets 30% of the total property

Remaining= 100 - 30 = 70

Son gets 50% of the remaining

50/100 × 70

35% property his son gets

His daughters gets rest of the property

rest = 35%

According to the question equation made is -

35 % of the total property will be handed to each of his daughter

35% of X = 49000

35/100× 2 × X = 49000

35/200 × X = 49000

X= 49000× 200/35

X= 280, 000

TOTAL PROPERTY OF THE MAN IS 280,000

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