Math, asked by Toastie, 4 months ago

A man gives 35% of his money to his elder son, 45% of the remaining money to his younger son and the rest to his wife. The wife received ₹ 64350. How much money he had in the beginning?

Answers

Answered by kashishhhhhhhhh
2

Answer:

rs. 1,30,660

Step-by-step explanation:

let man's money be x.

elder son got 35x/100=7x/20

younger son got 45/100×7x/20=63x/400

wife got 64350

64350+7x/20+63x/400=×

203x + 25,740,000= 400x

25,740,000=197x

x=130,659.89847715

x=130,660

Answered by Anonymous
0

A man gives 35% of his money to his elder son, 45% of the remaining money to his younger son and the rest to his wife. The wife received ₹ 64350. How much money he had in the beginning?

the man will get 230000 rupees

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