a man goes 1.2km due North and then 0.5km due West. find the least distance between his initial and final positions?
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Answered by
1
Use Pythagoras theorem and find the hypotenuse..... √1.2²+0.5² = 1.3 km
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0
1.2 square +0.5 square
= √12 sq. + √5 sq
√144 + 25 =
√169
=13 km
= 1.3 km
= √12 sq. + √5 sq
√144 + 25 =
√169
=13 km
= 1.3 km
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