Math, asked by khushiyadav312007, 7 months ago

A man goes 10 m due east and then 24 m due north. Find his distance from the starting point​

Answers

Answered by akshay241480
2

Answer:

Distance from the starting point is path dependent, so distance travelled is 10+24=34 m

Step-by-step explanation:

But the question here is to find the displacement

so, displacement=\sqrt{10^{2}+24^2 }= \sqrt{100+576}

\sqrt{676} m= 2\sqrt{169} m.

Hoping this is clear.

Answered by ritukumari15116
0

Answer:

When man go 10m due east and 24m due North then it form like base and height of a right angle triangle. After that the distance from he starts will be the hypotenuse of the right angle triangle. The formula of hypotenuse of right angle triangle is √base square+ height square. After putting this formula on this question we get

√10square+24square= √100+576= 586

Therefore 586 is the answer

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