Question

A man goes 10 m due east and then 24 m due north. Find the distance from the starting point.​

Answer 1

Answer:

Let the initial position of the man be O and his final position be B. Since the man goes 10 m due east and then 24 m due north. Therefore, ∆AOB is a right triangle right-angled at A such that OA = 10 m and AB = 24 m.

Answer 2

Answer:

answer is 26

${10 }^{2} + {24 }^{2} = {26}^{2} \\ 100 + 576 = 676$