a man goes 10 m due south and then 24m West how far is he from the starting point
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Assume the path traveled by the man as a triangle.
As the man goes in straight path and turns at the angle of 90°, by Pythagoras Theorem,
( hypotenuse )^2 = height^2 + base^2
hypotenuse^2 = ( 10 m )^2 + ( 24 m )^2
hypotenuse^2 = 100 m^2 + 576 m^2
hypotenuse^2 = 676 m^2
hypotenuse = 26 m
Therefore the total distance covered by the man is 26 m
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