Question

A man goes 10 m towards north then 24 m towards east then displacement is?​

Answer 1

$\text{It is given that the man moves 10 m North and 24 m east}$

$\text{Visualization of the question is given in the attachment}$

$AB = \text{24 m}, AC = \text{10 m}$

$\text{We must find }BC$

$\text{Applying the Pythagoras theorem}$

$\implies AB^{2} + AC^{2} = BC^{2}$

$\implies 24^{2} + 10^{2} = BC^{2}$

$\implies 576 + 100 = BC^{2}$

$\implies 676 = BC^{2}$

$\implies \sqrt{676} = BC$

$\implies \±26 = BC$

$\text{Since length cannot be negative}$

$\implies \boxed{BC = 26 \text{ m}}$