A man goes 10 meter due
east and then 24 meter due north. Find the distance from thestarting point.
Answers
Answered by
420
Hi ,
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Draw a rough diagram according to the given data in the problem,
we get a right angled triangle ,
distance traveled towards North = 24 m
distance traveled towards East = 10 m
distance from the starting point =Joining the to end points
= Hypotenuse of the right triangle
using Pythagoras Theorem ,
( Hypotenuse )² = ( base )² + ( height )²
= ( 10 )² + ( 24 )²
= 100 + 576
= 676
= ( 26 )²
Now required distance from starting point = √ ( Hypotenuse )²
= √(26)²
= 26 m
I hope this is useful to you.
***
N
Ι
Ι
____Ι______
E Ι W
Ι
S
Draw a rough diagram according to the given data in the problem,
we get a right angled triangle ,
distance traveled towards North = 24 m
distance traveled towards East = 10 m
distance from the starting point =Joining the to end points
= Hypotenuse of the right triangle
using Pythagoras Theorem ,
( Hypotenuse )² = ( base )² + ( height )²
= ( 10 )² + ( 24 )²
= 100 + 576
= 676
= ( 26 )²
Now required distance from starting point = √ ( Hypotenuse )²
= √(26)²
= 26 m
I hope this is useful to you.
***
Answered by
134
we get a right angled triangle ,
distance traveled towards North = 24 m
distance traveled towards East = 10 m
distance from the starting point =Joining the to end points
= Hypotenuse of the right triangle
using Pythagoras Theorem ,
( Hypotenuse )² = ( base )² + ( height )²
= ( 10 )² + ( 24 )²
= 100 + 576
= 676
= ( 26 )²
Now required distance from starting point = √ ( Hypotenuse )²
= √(26)²
= 26 m
I hope this is useful to you.
***
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