a man goes 10 meters due ease & then 24 meters due north. find the distance from the starting point
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let the distance traveled by mad due to east be AB
and distance traveled due to north be BC
to find the distance from the starting point
join A& C
it forms right angled triangle
by using hypotenuse theorem
AB²+BC²=AC²
10²+24²=AC²
100+576=AC²
AC²=676
AC=26
the distance from the starting point is 26
and distance traveled due to north be BC
to find the distance from the starting point
join A& C
it forms right angled triangle
by using hypotenuse theorem
AB²+BC²=AC²
10²+24²=AC²
100+576=AC²
AC²=676
AC=26
the distance from the starting point is 26
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