Question

a man goes 10m due east and then 24m due north. what is his present distance from the starting point?​

Answer 1

26m

sorry for not explanation

Answer 2

Answer:

26m

Step-by-step explanation:

Lets take the starting point as A, now the man goes 10m due east to point B, then moves on to point C, or goes 24m due north.

Now, if we look closely, joining AC presents before us a right angled triangle.

Now, the distance between A and C.

AC^2= AB^2+BC^2... pythagorus Theorem.

Therefore,

AC^2= 10^2+24^2

AC^2= 100+576

AC^2= 676

AC= root. 676

AC= 26.

Hope this helps.