A man goes 12 m due east and then 5m due south how far is he from the starting point
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Answered by
12
12² + 5² = 144 + 25
= 169= 13²
starting point = 13m
note : use Pythagoras theorem
Answered by
8
Application of Pythagoras Theorem !
Here the man first goes 12 m due east and then goes 5 m due south. Thus forming a right triangle as sides 12 m and 5 m respectively.
Now applying pythagoras theorem :
i.e. (perpendicular)² + (base)² = (hypotenuse)²
(12)² + (5)² = (dist. from origin)² (i.e.hypotenuse)²
144 + 25 = (dist. from origin)²
169 = (dist. from origin)²
√169 = dist. form origin
therefore, dist. from origin comes to be 13 m.
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