A man goes 12 m in east and 35 m due north . how far is he from his original posotion
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Answered by
3
His position forms a triangle.
Let us say triangle ABC.
AB=35m
BC=12m
AC=?
We know that acc. to pythagoras thrm.
2 2 2
H = P + B
Now,
2
AC= 35×35 + 12×12
AC=37m
Hope it helps...
Answered by
3
He is 37m far from his original position...
If I m right so please mark me as brainliest....
If I m right so please mark me as brainliest....
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