Question

A man goes 12 meter due east and 35 meter due north. How far is he from his original position?

Answer 1

the man is 35 meter far from his original position.

Answer 2

Hola Mate !!

Here's your answer :-

We can solve this by using Pythagoras Theorem

Let take,
OE,base = 12m
EN,hypotenuse = 35m
& NO,perpendicular = ?

${p}^{2} = {h}^{2} - {b }^{2} \\ = > p = \sqrt{ {35}^{2} - {12}^{2} } \\ = > p = \sqrt{1225 - 144} \\ = > p = \sqrt{1081} \\ = > p = 32.88m$
So, he is 32.88 far from his original position.

Hope it helps
Mark me as brainliest if it's correct