Question

a man goes 12 metre South reach A from O and then 9m West to reach B find the distance between O and B​

Answer 1

Step-by-step explanation:

$\huge\red{\underline{\underline{\bf Question}}}$

A man goes 12 metre South reach A from O and then he has to walk 9m West from A to reach B find the distance between O and B

$\huge\red{\underline{\underline{\bf Answer}}}$

Since all the directions (east, west , north and South) are perpendicular to each other we will use Pythagoras theorem to find solution of given question...

$\\ \\ \underline{oa = 12} \\ \\ \underline{ab = 9} \\ \\ ob = ?$

$by \: simply \: using \: pythagores \: theorem = > \\ \\ \implies {(ob)}^{2} = {(oa)}^{2} + {(ab)}^{2} \\ \\ \implies {(ob)}^{2} = {(12)}^{2} + {(9)}^{2} \\ \\ \implies {(ob)}^{2} = 144 + 81 \\ \\ \implies {(ob)}^{2} = 225 \\ \\ \huge \boxed { \implies ob = 15}$