Question

A man goes 120m due east and then 160m due north. How far is he from the starting point?​

Answer 1

Answer:

200 m is the answer.

Step-by-step explanation:

the man moved 120 m towards North

and then 160 m towards East

therefore displacement= s

120²+160²=s²

14400+25600=s²

s²=40000

s=200 m

Answer 2

Answer:

200 m

Step-by-step explanation:

see attachment

Distance between Initial and Final position=AC

Applying pythagoreas Theorem, we get

(AB)²+(BC)²=(AC)²

=>160²+120²=(AC)²

=>25600+14400=(AC)²

=>(AC)²=40000

=>AC=200 m

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