Question

A man goes 15 m due west and then 8 m due north. How far is he from his starting point?
(a) 289 m
(b) 17 m
(c) 18 m
(d) 64 m​

Answer 1

Answer:

17 m

Step-by-step explanation:

let ABC is a triangle.

A man starts from A and goes 15m due west.

so AB=15m

then from B 8m due north.

so BC=8m

Question is the distance from the starting poin to end point.

so AC= ?

Though ABC is a right angle triangle we can apply the formula (AB)^2+(BC^2=(AC)^2

=>sqrt{(AB)^2+(BC)^2}= AC

=>sqrt{15^2+8^2}=AC

=>sqrt{225+64}=AC

=>AC=sqrt(289)

=>AC=17m

Hence the final distance is 17m.

Answer 2

Answer:

(b) 17 m

Step-by-step explanation:

15 + 9 = 24 west

7 north

24 square + 7 square = 625

576 + 49 = 625

√625 = 25

therefore the distance to the origin equals 25 m