Question

A man goes 15 m due west and then 8 metre 2 north how far is he from the starting point

Answer 1

use pythagoras

15^2 + 8^2 = x^2

225 + 64 = x^2

x^2 = 289

x = root 289

x = 17

Answer 2

First he goes 15m to Wast and the he goes 8m to North

Thus he forms a Right Angled Triangle with distances 15m and 8m

Thus these two are the measures of both the adjacent sides of the Right Angle

So by applying Pythagoras Theorem -
(15)² + (8)² = (Distance from the Starting Point)²
225 + 64 = (Distance from the Starting Point)²
289 = (Distance from the Starting Point)²
Thus √289 = Distance from the Starting Point
The Distance from the Starting Point is 17m


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