Question

A Man goes 15 meters due west and then 8 meters
due north. How far is he from
starting point​

Answer 1

Answer:

he is 17 m far from his initial point.....

Step-by-step explanation:

hope this helps you.....

plzz mark it brainliest

Answer 2

First the person moves from A to B and then B to C.

His distance from the starting point is AC.

AC can be calculated using Pythagoras Theorem.

Applying Pythagoras theorem

(AB) 2+(BC)2=(CA) 2

(15) 2 +(8) 2 =(x) 2

225+64=(x) 2

x 2 =289

x=

$\sqrt{289}$

=17m