Question

A man goes 15 meters due west and then 8 meters due north. How far is he from the starting point?​

Answer 1

ANSWER

First the person moves from A to B and then B to C.

His distance from the starting point is AC.

AC can be calculated using Pythagoras Theorem.

Applying Pythagoras theorem

(AB)2+(BC)2=(CA)2

(15)2+(8)2=(x)2

225+64=(x)2

x2=289

x=289=17m

Answer 2

Answer:

your answer is 17 meter .

Explanation:

hope it is helpful for you..