Question

a man goes 15km due north and 20km due east. how for is he from his initial position

Answer 1

25 km. Added an attachment.

Answer 2

Here's your answer!!

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Distance travelled towards North = 15km
And distance travelled towards east =20 km

So,
By Pythagorean theorem ,we have:-
$= > {bc}^{2} = {ab}^{2} + {ac}^{2} \\ = > {bc}^{2} = {(20}^{2} ) + {(15)}^{2} \\ = > {bc}^{2} = 400 + 225 \\ = > {bc}^{2} = 625$
$= > {bc}^{2} = \sqrt{625} \\ = > bc = 25$

Hence,
He is 15 km car far from his initial point.

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See the attachment for figure.

Hope it helps you:)