A man goes 16 m due east and then 30 m due north,how far is he from the starting poin.
Answers
Answered by
0
Answer:
34m
Step-by-step explanation:
I hope it will help you
Attachments:
Answered by
0
Answer:
34m
Step-by-step explanation:
the man walks 16m east(AB) and then 30 m north(BC),
so joining all from start point forms a triangle with hypotenuse side(CA)
(CA)^2=(AB)^2 + (BC)^2
so 16 x 16 = 256
30 x 30 = 900
=256+900
=1156
CA= SQUARE ROOT OF 1156
CA=34
Similar questions