Math, asked by kulwantkaur9780, 2 days ago

A man goes 16 m due east and then 30 m due north,how far is he from the starting poin.

Answers

Answered by sharmadhruvveer14
0

Answer:

34m

Step-by-step explanation:

I hope it will help you

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Answered by smka15301431
0

Answer:

34m

Step-by-step explanation:

the man walks 16m east(AB) and then 30 m north(BC),

so joining all from start point forms a triangle with hypotenuse side(CA)

(CA)^2=(AB)^2 + (BC)^2

so 16 x 16 = 256

30 x 30 = 900

=256+900

=1156

CA= SQUARE ROOT OF 1156

CA=34

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