Math, asked by yasirali3289, 7 months ago

A man goes 24 km in due east and then He goes 10 km in due north. How far is he from the starting Point?

Answers

Answered by sarodeyash84
1

Answer:

34m

Step-by-step explanation: 34 m is its displacement i am sure u know what is displacement

Answered by Anonymous
17

Answer:

The man is 26 km away from his starting point.

Step-by-step explanation:

From figure,

we can clearly see that

A-Initial Point

C-Final Point

AB = 24 km

BC = 10 km

So, we have to find distance between point A and C i.e.

Length of AC

Applying Pythoagoreas Theorem, we get

(AB)²+(BC)²=(AC)²

=>24²+10²=(AC)²

=>(AC)² = 576+100 = 676

=>AC = √676

=>AC = √(2×2×13×13)

=>AC = 2×13

=>AC = 26 km

Hence,

The man is 26 km away from his starting point.

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