Question

A man goes 24 m due east and then 10m due north, How far is he away from his initial position?​

Answer 1

Answer:

Given:

A man goes 24 m due east and then 10m due north.

Find:

How far is he away from his initial position.

Given:

• 24 m => A man goes to east

• 10 m => And to north =

Calculations:

Distance = ( 24m )² + ( 10m )²

= 576 m² + 100 m² = 676 m²

= √676 m²

= 26 m

Answer 2

Step-by-step explanation:

$\large\orange{\boxed{\sf Hello Mate }}$

Let O be the initial position of the man.

Let him cover OA= 24m due east and then AB= 10m due north.

Finally, he reaches the point B. Join OB.

Now, in right ∆OAB, we have

(OB)² = ( OA²+ AB²)

:- {(24)² + (10)²}m² = (576+100)m² =676m²

$\large\implies{\sf </strong><strong>}$ OB = √676 = 26 metre.