Question

a man goes 24 m due west and then 10 m due north how far is he come from the starting point?​

Answer 1

Answer:

Step-by-step explanation:

In ABC

AB^2=AC^2+BC^2

AB^2=24^2+10^2

AB^2=576+100

AB^2=676

AB=26m

Therefore he is 26m away from the starting point

Answer 2

Given that,

OA=24 cm    AB=10 mOA=24 cm    AB=10 m

Let OB=x mLet OB=x m

In right angle △OABIn right angle △OAB

By using pythagoras theorem

OB2=OA2+AB2OB2=OA2+AB2

OB2=(10)2+(24)2OB2=(10)2+(24)2

OB2=100+576OB2=100+576

OB2=676OB2=676

OB=26m