a man goes 24 m due west and then 7 m due north . how far is he form the starting point ?
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A man goes 24m west and then 7m due north then join these both points
It will make a right angled triangle
Then solve by Pythagoras theorem
(24)2 +(17)2 =576+289=865
Then the man is 865m away from the starting point
It will make a right angled triangle
Then solve by Pythagoras theorem
(24)2 +(17)2 =576+289=865
Then the man is 865m away from the starting point
mohammaddalwai:
Srry by mistake I put 17
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solving the question by phythagoras theorem
bc square = ac square + ba square
bc = √ac sq +ba sq
bc = √24 sq + 7 sq
bc = √576 + 49
bc = √625
bc =25m
ps sorry diagram was not good :(
bc square = ac square + ba square
bc = √ac sq +ba sq
bc = √24 sq + 7 sq
bc = √576 + 49
bc = √625
bc =25m
ps sorry diagram was not good :(
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no. the diagram is good
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