Question

A man goes 24 m West again he goes 10m North Now at what distance is the man from his initial point

Answer 1

here 24 and 10 are sides making right angle

therefore 24square+10square=57600

240km distance

Answer 2

It can be solved by the formulae :-

A^2 + B^2 = C^2

24m^2 + 10m^2 = C^2

576m+100m=C^2

676m=C^2

√676m=C

26m=C