Question

A man goes 24m due west and 7m due north. How far is he from the starting point

Answer 1

$\huge\boxed{\mathbb{\fcolorbox{red}{yellow}{HEY MATE}}}$

$<b><i>$Let he is far from the starting point be x m.

A/q,

x² = 24² + 7²

$\implies$x² = 576 + 49

$\implies$x² = 625

$\implies$x = √625

$\implies$x = 25

Hence, he is far from the starting point is 25 m.

Answer 2

the diagram will be
|
|
|------------
west
so hare a right angle triangle and we have to find the hypotense

=> (24^2)+(7^2)
=> 576 +49
=> 625

square root of 625 = 25


hence he is 25 km away