Math, asked by Anonymous, 1 year ago

A man goes 24m due west and then 10m due north. How far is he from the starting point

Answers

Answered by Leukonov
78
His Displacemt From the starting point is:

= √[ (24)² + 10²]
=√[576+100]
=√[676]
=26m

So 26 m is your Answer.

Hope it helps,
Regards,
Leukonov.
Answered by KnowMore
38
A man goes 24m due west and then 10m due north. How far is he from the starting point?

Refer to the attachment please.

If we draw a diagram according to the question,we will see that it is making a triangle, and the perpendicular and the base is known, but the hypotenuse is not known. So we can find the hypotenuse by using the Pythagoras theorem,i.e hypotenuse^2=base^2+perpendicular^2

 =  >  \sqrt{ {24}^{2} +  {10}^{2}  }

 =  >  \sqrt{576 + 100}


 =  > \sqrt{676}


 =  > 26


So he is 26 m from starting point.
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