Question

A man goes 24m towards West and 10m towards North how far is he from the starting point

Answer 1

24 m west
and 10m north
it will make 90degree angle or we can say they will be perpendicular
so distance will be hypotenuse
d=√24^2+10^2
=26m

Answer 2

Answer:

26m

Step-by-step explanation:

A man goes 24m towards West i.e.AB = 24 m

Then he goes 10 m towards North i.e.BC=10 m

To find how far is he from the starting point i.e.Length of AC

We will use Pythagoras theorem

Hypotenuse^2=Perpendicular^2+Base^2

AC^2=AB^2+BC^2

AC^2=24^2+10^2

AC^2=676

AC= 26 m.

Hence he is 26 m far from the starting point.