A man goes 24m towards West and 10m towards North how far is he from the starting point
Answers
Answered by
28
24 m west
and 10m north
it will make 90degree angle or we can say they will be perpendicular
so distance will be hypotenuse
d=√24^2+10^2
=26m
and 10m north
it will make 90degree angle or we can say they will be perpendicular
so distance will be hypotenuse
d=√24^2+10^2
=26m
Answered by
6
Answer:
26m
Step-by-step explanation:
A man goes 24m towards West i.e.AB = 24 m
Then he goes 10 m towards North i.e.BC=10 m
To find how far is he from the starting point i.e.Length of AC
We will use Pythagoras theorem
Hypotenuse^2=Perpendicular^2+Base^2
AC^2=AB^2+BC^2
AC^2=24^2+10^2
AC^2=676
AC= 26 m.
Hence he is 26 m far from the starting point.
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