A man goes 3 km die north and then 4 km due east . How far is he away from his intial position . full explanation
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Answer:
By Pythagoras theorem, we get
Let AE = 3 km and ED = 4 km.
The distance from the initial point is :
AD² = AE² + ED²
= 3² + 4²
= 25
Then,
AD = 5 km.
Therefore, distance from initial point is 5 km.
Step-by-step explanation:
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