Question

. A man goes 3 km due north and then 4 km due east. How far is he away from his initial
position?​

Answer 1

Answer:

we need to calculate displacement

the answer will be 5km using Pythagoras theorem

Answer 2

If we trace the distance path and displacement path we will get a Right-angled triangle of 3km,4km and the displacement of the man from its initial position as the hypotenuse of the triangle.

Hence,

$the \: man's \: displacement \: = \sqrt{ {3}^{2} + {4}^{2} } \\ = \sqrt{9 + 16} = \sqrt{25} = 5km$