Math, asked by basantkumar7284, 1 year ago

A man goes 30 km due north and then 40 km due east how far away is he from his initial position

Answers

Answered by Anonymous
4

30 km upward then 40 km right.

This forming a right triangle. Hupotenuse or distance=

H^2= B^2+P^2

H^2= 30^2+40^2

H^2= 900km^2+1600km^2

H^2= 2500km^2

h = √2500 {km}^{2}

Hypotenuse= 50km

Hope it helps☺❤️

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