Question

A man goes 30 m due east and then 40 m due north. Find his distance from the starting point.

Answer 1

Hey mate!

Here's your answer!!

$\: \: \: \: \: \: {30}^{2} + {40}^{2} \\ = 900 + 1600 \\ = 2500 \\ \\ \sqrt{2500} = 50$
Hence, he is 50m away from starting point.

$hope \: it \: helps \: you.$

Answer 2

heya.....

your answer is:

50 meters.

It may help you....☺☺