Question

A man goes 30km due north and then 40km due east. how far away is he from his initial position?​

Answer 1

30 km upward then 40 km right. This forming a right triangle. Hupotenuse or distance=

H^2= B^2+P^2

H^2= 30^2+40^2

H^2= 900km^2+1600km^2

H^2= 2500km^2

h = \sqrt{2500 {km}^{2} }  

Hypotenuse= 50km

Hope it helps☺

Answer 2

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