A man goes 30m north then 40m east then find displacement
Answers
Answered by
3
Answer:
As the man is walking towards the 40m north first and then towards the east by a distance of 30m. ... Hence the displacement will be equal to the distance travelled by the man in the eastern direction.
Answered by
0
Answer:
p
Explanation:
let north (AB)=30m
and east (BC)=40m
i.e. displacement(AC)^2= AB^2+BC^2
'''''’'''''''''''''''. AC^2=30^2+40^2
:AC =√30×30+40×40
AC=50m answer
Attachments:
Similar questions