A man goes 35 m due west and then 12 m due
north. How far is he from the starting point?
Answers
Answered by
1
Answer:
it's forming a right angle triangle with hypotenuse as ur answer given by√(35^2+12^2)=√(1225+144)=√1369=
37 mts is ur answer....
Answered by
10
Answer:
let AB be the distance of men due North
and BC be the distance of men due west
=: AB = 12m. and BC = 35m
from fig. we get that triangle abc is right angled at c
so using Pythagoras theorem
AC² = AB² + BC²
AC² = 12² + 35²
AC² = 144 + 1225
AC² = 1369
AC = √1369
AC = 37m.
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