A man goes 35 metre due west and then 12 metre due north. How far is he from the starting point
Answers
Step-by-step explanation:
There are two answers to this question.
Answer 1
Well if we talk about distance , then we can say that the man is (35 + 12) meters away from the starting path.
Thus the distance between the man and the starting point is 47 meters.
This one answer to this question is 47 meters.
Answer 2
If we want to find the displacement of the man , then we can find it by pythagorean theorem.
Drawing and Understanding
On drawing the 35 m west line and 12 m north line , you have to join the current position of the man with the starting point by a single straight line.On doing this , you will notice that the figure formed resembles to a right angle triangle. And as we know , pythagorean theorem is a property of a right angle triangle which states that-
"sum of squares of the legs of the right angle triangle is equal to the square of the hypotenuse".
So according to the statement -
(35)^2 + (12)^2 = (displacement)^2.
See the figure you have drawn , you will notice that displacement is nothing but the hypotenuse of the right angle triangle formed.
1225 + 144 = (displacement)^2
(displacement)^2 =1369
displacement = 37.
Therefore another answer to this question is 37 meters.
(Note: For ppl who dont what is distance and displacement-
Distance is the actual path whereas displacement is the shortest path between any two points.)
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