Question

A man goes 3km north and then 4km to east. Find how far is he from his initial position

Answer 1

Answer:

5km

Step-by-step explanation:

By Pythagoras theorem, we know that

AC^2 = AB^2 + BC^2

= 4^2 + 3^2

= 16 + 9

= 25

AC = 5.

He has traveled 5km from the starting position.

Answer 2

Answer:

5km

Step-by-step explanation:

He goes 3km north and 4km east. if we joing the final position and the initial position, we get a triangle.

Hypotenuse = $\sqrt{3^{2} + 4^{2} }$

                     = $\sqrt{9+16}$

                     = $\sqrt{25}$

                     = 5

Hence, he is 5km far from his initial position.

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