Question

a man goes 3m. due east and 4m. due north . how far is he from starting point​

Answer 1

Answer:

HE IS 5M AWAY FROM THE STARTING POINT.

3^2+4^2=hy^2

hy=√25

hy=5 m

HOPE IT HELPS

Answer 2

Answer:

$\sqrt25=5 \text{ m}$

Step-by-step explanation:

We are given that -

• A man goes towards east = 3 m
• After he goes towards north = 4 m

To Find:

His Distance from starting Point

Solution :

Since we are given that a man goes 3m towards east and then he goes 4 m towards north direction.

By this travel he goes on a path that is Right Angle Triangle whose perpendicular side is  4 m and base is 3m .

To find the distance of the man from starting angle we have to calculate the hypotenuse of the right angle triangular path which is

=$\sqrt{\text{perpendicular}+\text{base}$

= $\sqrt{3^2+4^2$

= $\sqrt{9+16$

= $\sqrt{25}$

= 5 m

Hence his distance from starting point = 5 m

#SPJ2