Question

A man goes 5 km southwest and then turns left and goes 3.km. How far is he from the starting point?​

Answer 1

Answer:

Let the starting point be A ,

He moved 5 kms from A to B in South west direction .

From there he turned left to 3kms in left

Joining the end point C and starting point A , we will get a triangle ABC which is right angled at C.

[ As he turned left , he will be parallel to starting point]

We have to find AC

By using pythagoras theorem,

I.e (Hypotenuse)^2 = (Base)^2 + (altitude)^2

AB^2 = BC^2 + AC^2

AC^2 = 5^2 - 3^2

AC^2 = 25 - 9

AC =$\sqrt{16}$km = 4 km

Answer 2

Answer:

5.83 km

you can draw a right angle triangle with the given value . lets take 5 km as 'p'

3 km as 'b' and lets x be 'h'.  now from the relation between p h and b you can get the answer.