A man goes 5 m due west and then 12 m due north. How far is he from the starting point?
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Answered by
1
Answer:
12m far he walk from the starting point
Answered by
5
Answer:
13 m
Step-by-step explanation: Let his starting point be a point O.
Let him go 5m in the west direction till a point A, then turn north and go 12m to a point B. We can see that the points O, A and B form a right angled triangle, with OA=5m, and AB=12m, we need to find OB.
Now by Pythagoras, OA²+AB²= OB²
So 5²+12²=OB²
25+144= OB²
OB=√169
∴OB=13m
Hence, he is 13m away from his starting point.
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