Question

A man goes 5 m in East and then 12 m in North direction. Find the distance from the starting point.​

Answer 1

Answer:

a right angled traingle will be formed with the unknown distance as rhe hypotenuse. let the diatance be x

by pythagoras theorem:

x² = 5²+12²

x² = 25+144

x² = 169

x = 13m

distance from starting point = 13m.

Hope it helped.

Answer 2

Answer:

The answer is 13 m

Step-by-step explanation:

Let, A be the point where the man is standing.

Let, A be the point where the man is standing. Let, B be the point where the man reaches after travelling 5m east

Let, A be the point where the man is standing. Let, B be the point where the man reaches after travelling 5m eastand C be the final point where the man reached after travelling 12m north from point B.

Now,

ABC forms a right triangle.

we know,

according to Pythagoras theorem,

${h}^{2} = {a}^{2} + {b}^{2}$

Therefore,

${h}^{2} = {12}^{2} + {5}^{2} \\ = > {h}^{2} = 144 + 25 \\ = > {h}^{2} = 169 \\ = > h = \sqrt{169} \\ = 13$

Therefore distance between the starting point and the final point is 13m