Question

A man goes 5 m in east and then 12 m in north direction. Find the distance from the staring point.

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Answer 1

Step-by-step explanation:

Let the initial position of the man be O and his final position be B. Since the man goes 10 m due east and then 24 m due north. Therefore, △AOB is a right triangle right-angled at A such that OA=10 m and AB=24 m.

By pythagoras theoram, we have

OB^2 =OA^2 +AB^2

OB^2 =10^2 +24^2

=100+576=676

OB= √676 =26m

Hence, the man is at a distance of 26m from the starting point.

Answer 2

Answer:

The ans is 13.

Step-by-step explanation:

This is due to the above explanation