A man goes 5m in east and then in north direction. Find the distance from the starting point .give answer of this question
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he wii travel 10 metre
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Answer:
ABC is right angled triangle ,
By Pythagoras property of triangle
AC² = BC² + AB²
AC² = 12² + 5²
AC²= 144 + 25
AC² = 169
AC²= 13²
AC = 13 cm
Shortest distance from starting point = 13cm
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