Question

a man goes 7 m due to north and then 24m due to East how far is he from the starting point

Answer 1

${24}^{2} + {7}^{2} = 576 + 49 = 625 \\ \sqrt{625 } = 25m$

Answer 2

$\: \: \: \: \: \: Your \: \: \: \: \: Answer \\ - - - - - - - - - - - - -$

$Let \: \: his \: \: distance \: \: from \\ the \: \: starting \: \: point \: \: be \: \: x.$

$Now, \: \: By \: \: Pythagoras \: \: Theorem$

$\: \: \: \: x {}^{2} = 7 {}^{2} + 24 {}^{2}$

$= > x {}^{2} = 49 + 576$

$= > x {}^{2} = 625$

$= > x = \sqrt{625}$

$= > x = 25$

$Hence, \: \: his \: \: distance \: \: from \\ the \: \: starting \: \: point \: \: is \: 25m.$