A man goes 70m due east and then 240 m due north.find how far he is from the starting point
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Let OA be the distance covered due east=70m
Let AB be the distance covered due north=240m
In right ΔOAB by Pythagoras theorem we have
OB²=AB²+OA²
OB²=(240)²+(70)²
OB²=4900+57600
OB²=52500
OB=250m
Hence the distance between his starting and final point is 250m
Let AB be the distance covered due north=240m
In right ΔOAB by Pythagoras theorem we have
OB²=AB²+OA²
OB²=(240)²+(70)²
OB²=4900+57600
OB²=52500
OB=250m
Hence the distance between his starting and final point is 250m
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