A man goes 7metres due to east and then 24 metres due to north then his distance from the starting point is
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according to figure AC^2+BC^2=AB^2
hence (24)^2+(7)^2=AB^2
& 576+49=AB^2
AB^2=625==(25)^2
AB=25
hence ur answer is 25m
hence (24)^2+(7)^2=AB^2
& 576+49=AB^2
AB^2=625==(25)^2
AB=25
hence ur answer is 25m
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vishal2266:
if it is correct plz mark as brainliest
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Hence, the man distance from the starting point is 25m.
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