Question

A man goes 8 m due west and then 15 m due north. how far away is he from his initial position?​

Answer 1

Answer:

ANSWER IS 17

Step-by-step explanation:

8M WEST

15m north

make a triangle

use Pythagoras theorum

8²+15²=17²

Answer 2

Answer:

• given that

man goes to 8m west and

15m north

let AB = 8m , BC =15m & AC =?

we use phytagoras's theorem

AC^2 = (AB + BC)^2

= (15 + 8 )^2

= (225 + 64)

= (289)

AC^2 = 289

AC = √289

AC = 17m

So, the distance of initial position is 17m